while (char_ok(i) == 0)

[gcmaxxon]

Hi,

Here is a piece of "for next" coding , Ops!, wrong language,

that I do not quite understand.

 

Quote:

For example (i.e.) :

 

i = 0

while (char_ok(i) == 0)

{i = i + 1; }

...

append_char_name(i);

...

I guess my questions are : what character's name is appended?

and just how is it displayed to the player?

 

Thanks before hand for any help.

gcmaxxon

[Drakefyre]

The name is appended to the buffer, which holds strings that you are appending. To get each character's name, the appending name line should go inside of the curly braces.

[Kelandon]

I'm guessing that he got that code out of one of my scenarios — the bracketing is distinctive.

 

The idea is that the while loop finds the first living character. It starts with 0, and if 0 is dead, it checks 1, and so on until it finds the party leader.

 

So i is the first living character, and that character's name is appended to the text buffer. That displays nothing. Notice a few lines later that there's this:

 

Code:

 get_buffer_text(dlgstr);message_dialog(dlgstr,""); 

Or something along those lines. The get_buffer_text saves the text buffer to dlgstr, and then message_dialog pops up dlgstr.

 

This is the way to make a message box address the leading character by name.

[gcmaxxon]

Hi,

Yes, you are correct. It is coding from "Castle Pudideum". I thought this was one (maybe the only way) way of displaying one of the party's name.

Can I use your "dlgstr" coding?

Thanks for the help.

 

gcmaxxon

[Kelandon]

Yes, you can use it.