# Let #f(x)=x^2-2x+5# and #g(x)=4/(x-1)#, how do you find #(fog)(3)#?

##### 1 Answer

Dec 27, 2016

#### Explanation:

Start by finding (f￮g)(x)

To find this function, substitute

#x=4/(x-1)"That is g(x) into " f(x)#

#rArr(f￮g)(x)=(4/(x-1))^2-2(4/(x-1))+5#

#=16/(x-1)^2-8/(x-1)+5# Now substitute x = 3

#rArr(f￮g)(3)=16/(3-1)^2-8/(3-1)+5#

#=16/4-8/2+5=4-4+5=5#